Question

Sa se calculeze presiunea in Pa a 2 moli de oxigen ce ocupa 1 litru si se afla la temperatura de 27 grade Celsius.Ce masa are gazul?

Answer 1

$PV=nRT; R=0.082J/mol*K$
$n=2 moli O2; V=1L; t=27grC$
$transformam gradele celsius in Kelvin$
$t=27+273.15=300.15K=T$
$T=300.15K$
$P= \frac{nRT}{V} = \frac{2*0.082*300.15}{1} =49.2246$