Question

Sa se determine masa, numarul de moli si numarul de molecule continute in conditii normale de 89,2 L CO2

Answer 1

n=89,2:22,4=3,98 moli CO2
m=3,98*44=35,98g CO2
1molCO2.........6,023*10^23molecule CO2
3,98moli CO2..........x
x=3,98*6,023*10^23molecule CO2