Question

Sa se determine masa unui metru cub de aer la 17 grade Celsius si 624 mmHg.

Answer 1

P×V=n×R×T

P=624 mmHg=624/780 atm =0.8 atm
T = 17 C = 17+273=290 K
V = 1000 l
n= P×V/(R×T)=0.8×1000/(0.082×290)=33.64 moli
1mol aer= 28.9g
33.64moli = 33.64×28.9g =972.25 g
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