Question

Sa se determine rația unei progresii aritmetice știind ca a10-a2=6.

Answer 1

$a_{10}-a_2=6 \\\\\\ a_{10}=a_1+(n-1)d \\\\ a_{10}=a_1+(10-1)*d \\\\ a_{10}=a_1+9d \\\\\\ a_2=a_1+(n-1)*d \\\\ a_2=a_1+(2-1)*d \\\\ a_2=a_1+d \\\\\\ a_{10}-a_2=6 \\\\ a_1+9d-a_1-d=6 \\\\ 8d=6 \\\\ d= \frac{\not6}{\not8} \\\\\\ \boxed{d= \frac{3}{4}-ratia}$