Question

sa se determine x€r astfel incat tripletul de numere sa fie in programele aritmetica
3x-10;5x-12;x^-2

Answer 1

3x-10; 5x-12; x²-2   in progresie aritmetica

=> 5x-12=(3x-10+x²-2)/2

10x-24=x²+3x-12

x²+3x-10x-12+24=0

x²-7x+12=0

Δ=49-48=1

x1=(7+1)/2=4

x2=(7-1)/2=3

x∈{3, 4}