Question

Sa se impara numarul 301 in trei parti invers proportionale cu numerele 12;10 si 18.

Answer 1

12x=k    x=k/12
10y=k    y=k/10
18z=k    z=k/18
x+y+z=301
k/12+k/10+k/18=301
15k+18k+10k=54180
43k=54180
k=1260
x=k/12 =1260/12=105
y=k/10 =1260/10=126
z=k/18 =1260/18=70