Question

Sa se imparta numarul 301 in trei parti invers proportionale cu numerele 12, 10 si 18.

Va rog mult urgent!!!

Answer 1

Răspuns:

Fie a,b,c, cele trei parti invers proportionale => 12 ·a=10·b=18·c=k=>

a=k/12 b=k/10 iar c=k/18 

si a+b+c=301 =>k/12 +k/10 +k/18 =301(aducem la acelasi numitor)

cmmc(12,10,18)=180 =>

15 k +18 k+ 10 k=301 ·180=54180 

43k=54180

k=1260

a=1260/12=105

b=1260/10=126

c=1260/18=70

Explicație pas cu pas:

Answer 2

Răspuns:

a=105

b=126

c=70

Explicație pas cu pas:

a+b+c=301

a*12=b*10=c*18=k

cmmmc(12;10;18)=2²*5*3²=180

180:12=15k

180:10=18k

180:18=10k

k/12+k/10+k/10=15k/180+18k/180+10k/180=43k/180=301

43k=301*180

43k=54180

k=54180:43

k=1260

a=1260/12

a=105

b=1260/10

b=126

c=1260/18

c=70

105+126+70=301