Question

Sa se rationalizeze radical 3 -radical 2 supra radical 3 + radical 2

Answer 1

$\frac{ \sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}= \frac{(\sqrt{3}-\sqrt{2})^2}{(\sqrt{3}-\sqrt{2})(\sqrt{3}+\sqrt{2})}=\frac{3+5-2\sqrt{6}}{3-2}=5-2\sqrt{6}$