Question

Sa se rezolve ecuatia: (n+1)!(n+1)=6*(n+2)!
(!)= factorial

Answer 1

n! (n+1)^2=6*n!*(n+1)(n+2)
n+1=6*(n+2)
5n=-11 ????

Answer 2

(n+2)!=(n+1)!(n+2)
(n+1)!(n+1)=6(n+1)!(n+2) impartim ecuatia la (n+1)!
n+1=6(n+2)
n+1=6n+12
6n+12=n+1
6n-n=1-12
5n=-11
n=-11/5 nu e nr natural deci ecuatia nu are solutii