Question

Sa se rezolve ecuatiile :
a) 2arcsin x-pi=0
b) 6arccos √x =pi

Answer 1

a)$2arcsinx- \pi =0,sau,arcsinx= \frac{ \pi }{2},aplic,"sin",rezulta,sin(arcsinx)$=$sin \frac{ \pi }{2},deci,x=1.$
b)Avem de fapt ec.: $arccos \sqrt{x} = \frac{ \pi }{6},aplic,"cos",rezulta,cos(arccos \sqrt{x} )=cos \frac{ \pi }{6},deci, \sqrt{x} =$$\frac{ \sqrt{3} }{2},sau,x= \frac{3}{4}$