Question

Sa se rezolve ecuatiile:x*2 +10x+9=0;5x*2+3x-2=0;3x*2+5x-2=0;
x*2+2x+3=0;x*2-3 radical din 2x+4=0; x*2+4x-radical din 3+1=0 ; *(inseamna la putere)

Answer 1

x^2+10x+9=0
delta=64 => x1=-1 x2=-9

5x^2+3x-2=0
delta =49 => x1=0,4 x2=-1

3x^2+5x-2=0
delta=49 => x1=0,33 x2=-2

x^2+2x+3=0
delta=-8 deci nu avem solutii

x^2-3√2x+4=0
delta=8 => x1=5√2/2 si x2=√2/2

x^2+4x-√3+1=0
delta=15+4√3 => x1=-4+radical din 16+4√3/2 si x2= -4- radical din 16+4√3/2