Question

Sa se rezolve in R ecuatia : (2+3i)x+(5+4i)y=19-11i

Answer 1

(2+3i)x+(5+4i)y=19-11i
2x+3xi+5y+4yi=19-11i
2x+5y+(3x+4y)i=19-11i
Si formam sistemul:
{ 2x+5y=19
{ 3x+4y=-11
Si rezolvam fie prin metoda substitutiei, fie prin reducere.
{ 6x+15y=57
{ 6x+8y=-22
Scadem cele doua ecuatii:
15y-8y=57-(-22)
7y=79
y=79/7
3x+4*79/7=-11
3x+316/7=-11
3x=-11-316/7
3x=-393/7
x=-393/21