Question

sa se rezolve in R ecuatia!Dau coroana.​

Answer 1

Răspuns:

Explicație pas cu pas:

I  ⁶⁾5x - ²⁾1/3 I  ≥ ³⁾1/2  <=>

I (30x-2)/6 I ≥ 3/6 <=>

I 30x-2 I ≥ 3

I 30x - 2 I = { 30x-2  , pentru x ≥ 1/15

                  {-30x+2 , pentru x < 1/15

30x-2 ≥ 3  => 30x ≥ 5  => x ≥ 1/6

-30x+2 ≥ 3  => 30x ≤ -1 => x ≤ -1/30

x ∈ (-∞ ; 1/30] ∪ [1/6 ; +∞)

Answer 2

Răspuns:

|5x - 1/3| ≥ 1/2

5x-1/3 ≥ 1/2, 5x - 1/3 ≥0

-(5x-1/3) ≥1/2, 5x - 1/3 <0

x≥1/6, x≥1/15

x≤ -1/30 , x< 1/15

x€[1/6;+∞)

x€(-∞;- 1/30]

x€(-∞;- 1/30] U [1/6;+∞)

EVERGREEN