Question

Sa se scrie ecuatia tangentei la grafic in punctul A (1,0)

Answer 1

$f(x)= \frac{ln^2x}{x}, derivata:f'(x)= \frac{2lnx-ln^2x}{x^2},iar,f'(1)=0=panta,tangentei$=mA , Ecuatia in general este:  $y-y_{A}=m_{A}(x-x_{A}),deci,y-f(x_{A})=0(x-1),sau,y=0$, chiar axa OX.