Question

Sa se scrie nr. 2003 la puterea 2003 ca suma de 2003 numere naturale consecutive. Multumesc

Answer 1

       2003+2003
2003
:))) eBN:)P

Answer 2

n +(n+1) +(n+2)+.......+(n+2002) = 2003^2003
2003·n + (1+2+3+........+2002) = 2003^2003
2003n + 2002·2003/2 = 2003^2003
n +1001 = 2003^2002
n = 2003^2002 - 1001
2003^2003 =(2003^2002 -1001)+(2003^2002 -1000) +...+(2003^2002 - 1001+2002)
= (2003^2002 - 1001) + (2003^2002 - 1000)+......+(2003^2002 +1001)