Question

Sa se simplifice fractia

f(x) =$\frac{ x^{2} +4x}{ x^{2} -16}$

Answer 1

=x²+4x/(x-4)(x+4)=x(x+4)/(x-4)(x+4)=x/x-4

Answer 2

[tex] \frac{x^2+4x}{x^2-16 } = \frac{x^2+4x}{x^2-4^2} = \frac{x(x+4)}{(x-4)(x +4)} =\boxed{ \frac{x}{x-4} }[/tex]