Question

Sa se simplifice raportul x²-5x+4 supra 2x-8 unde x∈R / {4}.

Answer 1

x²-5x+4Δ=b²-4ac=25-4×4=9
Δ=9
x1=(-b+√Δ)/2a=(5+√9)/2=8/2=4
x2=(-b-√Δ)/2a=(5-3)/2=2/2=1
deci ecuatia initiala devine:  (x-4)(x-1)
2x-8 dam factor comun 2 ⇒2(x-4)
deci
$\frac{ x^{2} -5x+4 }{2(x-4)} \\ = \frac{(x-4)(x-1)}{2(x-4)} \\ = \frac{x-1}{2}$