Question

Så se determine termenii de rang 10, 15, 20 al progresiei aritmetice: a) d) -2/3, -2(6), -4 2/3,... ??​

Answer 1

Răspuns:

Explicație pas cu pas:

-2,(6) = -(26 -2)/9 = -24/9 = -8/3 +

r = -8/3 - (-2/3) = -8/3 +2/3 = -6/3  = -2

T10 = -2/3 +9(-2) = -2/3 -18 = -2/3 -54/3 = -56/3

T15 = -2/3 +14(-2) = -2/3 -28 = -2/3 -84/3 = -86/3

T20 = -2/3 +19(-2) = -2/3 -38 = -2/3 -114/3 = -116/3