Question

salut care ma poate ajuta la exercitile acestea imi trebuie pentru ora3 plz
2.3

Answer 1

Răspuns:

Explicație pas cu pas:

ex 2

1/(√3 - 1) = (√3 + 1) / (√3 - 1)(√3 + 1) = (√3 + 1) / (3 - 1) = (√3 + 1) / 2

1 / (√7 - √5) = (√7 + √5) / (√7 - √5)(√7 + √5) = (√7 - √5) / (7 - 5) = (√7 - √5)/2

1/2√5 = √5/10

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-√3/√75 = -√3 / √(3 * 25) = -√3 / 5√3 = -1/5

3√2/2√3 = 3√2*√3 / 2√3*√3 = 3√6/6 = √6/2

5√7/3√5 = 5√7*√5 / 3√5*√5 = 5√35 / 15 = √35/3

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-1/√300 = -1 / 10√3 = -√3 /30

3/√250 = 3/5√10 = 3√10/50

2,4/√5 = 24/10√5 = 12/5√5 = 12√5 / 25

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Ex 3

(x + 2) / (x^2 - 4) = (x + 2) / (x + 2)(x - 2) = 1 / (x - 2)

(3x - x^2) / (9 - x^2) = x(3 - x) / (3- x)(3 + x) = x / (3 + x)

(4x^2 - 1)/(6x - 3) = (2x + 1)(2x - 1) / 3(2x - 1) = (2x + 1) / 3

(25x^2 - 4) / (15x + 6) = (5x - 2)(5x + 2) / 3(5x + 2) = (5x - 2)/3

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Ex 1

Pui conditia ca numitorii sa nu fie 0

x aprtine lui R-0

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x apartine lui R - 2

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x apartine lui R-6

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x apartine lui R - (-4)

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x apartine lui R - (-1,2)