Question

scoate de sub radical ​

Answer 1

Răspuns:

Explicație pas cu pas:

$\sqrt\frac{63}{50}= \sqrt\frac{7*9}{50}=\sqrt\frac{7*3^2}{50}=3\sqrt\frac{7}{50}\\\sqrt\frac{405}{12}=\sqrt\frac{81*5}{12}=\sqrt\frac{9^2*5}{12}=9\sqrt\frac{5}{12}\\\sqrt{500}=\sqrt{25*20}=\sqrt{5^2*20} =5\sqrt{20} \\\sqrt{108} =\sqrt{36*3}=\sqrt{6^2*3}=6\sqrt{3}$

Answer 2

Explicație pas cu pas:

V63/50 = V7×3²/50 = 3 V7/50

V500 = V5²×20 = 5V20

V108 = V6²×3 = 6V3

V405/12 V9²×5/12 = 9 V5/12