Question

scoate factor comun a: a)ab+ac; b)ab+7a; c)ab+a; d)ab-ac ; e) ab-3a; f)ab-a; g)ab+ac-ad ; h)ab+5a-ac; i)ab+ac-a

Answer 1

a)  ab + ac = a × ( b + c )

b)  ab + 7 a = a × ( b + 7 )

c) ab + a = a × ( b + 1 )

d) ab - ac = a × ( b - c )

e)  ab - 3a = a × ( b - 3 )

f)  ab - a = a × ( b - 1 )

g)  ab + ac - ad = a × ( b + c - d )

h )  ab + 5 a - ac = a × ( b + 5 - c )

i)  ab + ac - a = a × ( b + c - 1 )