Question

Scoateti factor comun pe (x+1)
a) (x+1)(x-0,3)+(x+1)
b) (x+1)²+(x+1)(x-1)
c) (x-1)²(x+1)-(x+1)²
d) (x+1)³-(x+1)(x+2)

Answer 1

a)    (x+1)(1×0,7+1)=(x+1)×1.7
b)    (x+1)(1²-1)=(x+1)×0=0
c)    (x+1)(1×1-1²)=0
d)    (x+1)(1³-1×2)=(x+1)(1-2)

Answer 2

A)    (x+1)(x-0,3)+(x+1)=(x+1)(x-0,3+1)=(x+1)(x+0,7)=x²+1,7x+0,7
B)    (x+1)²+(x+1)(x-1)=(x+1)(x+1+x-1)=(x+1)·2x=2x²+2x
C)    (x-1)²(x+1)-(x+1)²= (x+1)((x-1)²-(x+1))=(x+1)(x²-2x+1-x-1)=(x+1)(x²-3x)
D)    (x+1)³-(x+1)(x+2)= (x+1) ((x+1)²-(x+2))=(x+1)(x²+2x+1-x-2)=(x+1)(x²-x-1)
   Aici la tot e factorul comun       (x+1)