Question

Scoateti factorii de sub radical , rationalizati numitorii si apoi calculati:
a) 3/2√18+2/√50
b) 5/2√12-2/√75
c) 2/√20+3/2√45
d) 7/√24-1/2√54
e) 2/√28-5/2√63
f) 9/2√75-8/√48

Answer 1

a)3/2√(9·2)+2/√(25·2)=3/2·3√2+2/5√2=1/2√2+2/5√2=9/10√2
b)=5/4√2-2/5√3=17/20√3
c)=2/2√5+3/6√5=3/2√5
d)=7/2√6-1/6√6=20/6√6=10/3√6
e)=2/2√7-5/6√7=1/6√7
f)=9/(2·5√3)-8/4√3=9/10√3-8/4√3=9/10√3-2√3=-11/10√3