Question

Scrie sub forma
de fractii ordinate ireductibile:
1,2;0,75;4,12;0,(3);2,(36);4,(125);0,3(12);8,0(6);12,12(345)

Answer 1

[tex]1,2=\frac{12}{1}=\frac{6}{5}\\ 0,75=\frac{75}{100}=\frac{3}{4}\\ 4,12=\frac{412}{100}=\frac{103}{25}\\ 0,(3)=\frac{3}{9}=\frac{1}{3}\\ 2,(36)=2\frac{36}{99}=2\frac{4}{11}=\frac{26}{11}\\ 4,(125)=4\frac{125}{999}\\ 0,3(12)=\frac{312-3}{990}=\frac{309}{990}=\frac{103}{330}\\ 8,0(6)=8\frac{6}{90}=8\frac{1}[15}=\frac{121}{15}\\ 12,12(345)=12\frac{12345-12}{99900}=12\frac{12332}{99900}=12\frac{3083}{24975}[/tex]