Question

Scrieti formulele chimice ale substantelor care contin fiecare din elementele:Li,Na,K,Mg,Ca,Ba,Al,Zn,Fe,Cu si gruparea hidroxil,OH cu valenta=1.Pentru cinci din formulele gasite precizati:
Raportul atomic
Raportul masic
Masa molara
Compozitia procentuala
Cat mai repede va rog!!

Answer 1

LiOH
NaOH
KOH
Mg(OH)2
Ca(OH)2
Ba(OH)2
Al(OH)3
Zn(OH)2
Fe(OH)2
Fe(OH)3
Cu(OH)2


LiOH:
raport atomic: 1:1:1
raport masic: 7:16:1
masa molara: 7+16+1=24 g/mol
compozitia procentuala:
24 g LiOH...7 g Li...16 g O...1 g H
100 g LiOH...x g Li...y g O...z g H

x=29.16% Li
y=66.66%O
z=4,16%H


KOH:
raport atomic: 1:1:1
raport masic: 39:16:1
masa molara: 39+16+1=56 g/mol
compozitia procentuala:
56 g KOH...39 g K...16 g O...1 g H
100g KOH...x g K...y g O...z g H

x=69.64% K
y=28.57% O
z=1.78% H


Mg(OH)2:
raport atomic: 1:2:2
raport masic: 24:32:2=12:16:1
masa molara: 24+32+2=58 g/mol
compozitia procentuala:
58 g Mg(OH)2...24 g Mg...32 g O...2 g H
100 g Mg(OH)2...x g Mg...y g O...z g H

x=41.37% Mg
y=55.17% O
z=3.44% H


Al(OH)3:
raport atomic: 1:3:3
raport masic: 27:48:3=9:16:1
masa molara: 27+48+3=78 g/mol
compozitia procentuala:
78 g Al(OH)3...27 g Al...48 g O...3 g H
100 g Al(OH)3...x g Al...y g O...z g H

x=34.61% Al
y=61.53% O
z=3.84% H


Cu(OH)2:
raport atomic: 1:2:2
raport masic: 64:32:2=32:16:1
masa molara: 64+32+2=98 g/mol
compozitia procentuala:
98 g Cu(OH)2...64 g Cu...32 g O...2 g H
100 g Cu(OH)2...x g Cu...y g O...z g H

x=65.3% Cu
y=32.65% O
z=2.04% H