Question

scrieti intregii fracti
a 14 supra 3
5 supra 2
7 supra 4
21 supra 5
43 supra 12
120 supra 11

b 37 supra 3
29 supra 4
78 supra 25
402 supra 15
104 supra 7
254 supra 24

c 302 supra 7
506 supra 14
48 supra 9
427 supra 32
405 supra 21
va rog ajutatima​

Answer 1

Răspuns:

Explicație pas cu pas:

a) $\frac{14}{3} = \frac{4*3+2}{3} = 4\frac{2}{3}$

    $\frac{5}{2} = \frac{2*2+2}{3} =2\frac{1}{2}$

    $\frac{7}{4} = \frac{1*4+3}{4} =1\frac{3}{4}$

   $\frac{21}{5} = \frac{4*5+1}{5} =4\frac{1}{5}$

   $\frac{43}{12} = \frac{3*12+7}{12} =3\frac{7}{12}$

   $\frac{120}{11} = \frac{10*11+10}{11} =10\frac{10}{11}$

b) $\frac{37}{3} = \frac{12*3+1}{3} = 12\frac{1}{3}$

   $\frac{29}{4} = \frac{7*4+1}{4} = 7\frac{1}{4}$

   $\frac{402}{15} = \frac{26*15+12}{15} = 26\frac{12}{15}$

   $\frac{104}{7} = \frac{14*7+6}{7} = 14\frac{6}{7}$

   $\frac{254}{24} = \frac{10*24+14}{24} = 10\frac{14}{24}$

c)  $\frac{302}{7} = \frac{43*7+1}{7} = 43\frac{1}{7}$

    $\frac{506}{14} = \frac{36*14+2}{7} = 36\frac{2}{7}$

    $\frac{48}{9} = \frac{5*9+3}{9} = 5\frac{3}{9}$

    $\frac{427}{32} = \frac{13*32+11}{32} = 13\frac{11}{32}$

    $\frac{405}{21} = \frac{19*21+6}{21} = 19\frac{6}{21}$