Question

Scrieti numarul 300 ca suma a patru numere direct proportionale cu 2,3,4 si 6 . Va rog !

Answer 1

a, b, c, d- numerele
{a, b, c, d}⇒ dp cu {2;3;4;6}
a÷2=b÷3=c÷4=d÷6=K
a=2K
b=3K
c=4K
d=6K
2K+ 3K+ 4K+ 6K= 300
15K= 300
K= 20
a=2×20= 40
b=3×20= 60
c=4×20= 80
d=6×20= 120

Answer 2

{A,B,C,D}D.P.{2,3,4,6}
A supra 2 =B supra 3=C supra 4=D supra 6⇒K
A=2k
B=3K
C=4K
D=6K
A+B+C+D=300⇒2K+3K+4K+6K=300
15K=300
K=300/15
K=20
A=2K⇒A=2×20=40
B=3K⇒B=3×20=60
C=4K⇒C=4×20=80
D=6K⇒D=6×20=120
Proba:40+60+80+120=
100+80+120
180+120+300