Matematică, întrebare adresată de blesslena, 9 ani în urmă

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Răspuns de Utilizator anonim
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\displaystyle \left[\left( \frac{3}{5} \right)^6:\left(5-4 \frac{2}{5} \right)^4+2:1 \frac{1}{4} -\left( \frac{3}{5} \right)^2\right]:1 \frac{3}{5}= \\ \\ =\left[\left( \frac{3}{5}  \right)^6:\left(5- \frac{5 \cdot4+2}{5} \right)^4+2: \frac{4 \cdot 1+1}{4} -\left( \frac{3}{5} \right)^2\right]: \frac{5 \cdot 1+3}{5} =
\displaystyle =\left[\left( \frac{3}{5} \right)^6:\left(5- \frac{20+2}{5} \right)^4+2: \frac{4+1}{4} -\left( \frac{3}{5} \right)^2\right]: \frac{5+3}{5} = \\ \\ =\left[\left( \frac{3}{5} \right)^6:\left(5- \frac{22}{5} \right)^4+2: \frac{5}{4} -\left( \frac{3}{5} \right)^2\right]: \frac{8}{5} =
\displaystyle =\left[\left( \frac{3}{5} \right)^6:\left( \frac{25-22}{5}\right)^4 +2 \cdot  \frac{4}{5} -\left( \frac{3}{5} \right)^2\right]\cdot  \frac{5}{8} = \\ \\ =\left[\left( \frac{3}{5} \right)^6:\left( \frac{3}{5} \right)^4+ \frac{8}{5} -\left( \frac{3}{5} \right)^2\right] \cdot  \frac{5}{8} =\left[\left( \frac{3}{5} \right)^{6-4}+ \frac{8}{5} -\left( \frac{3}{5} \right)^2\right]\cdot \frac{5}{8} =
\displaystyle =\left[\left( \frac{3}{5} \right)^2+ \frac{8}{5} -\left( \frac{3}{5} \right)^2\right] \cdot  \frac{5}{8} = \frac{\not8}{\not5} \cdot  \frac{\not5}{\not8} =\boxed{1}
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