Question

Scrieti sub forma de raport algebric ireductibil:
$\frac{ a^{2}-4a+4 }{b+ b^{3} }$:$\frac{2-a}{ b^{2}+1 }$
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Answer 1

[tex]\frac{a^2-4a+4}{b+b^3}:\frac{2-a}{b^2+1}=\\ \frac{(a-2)^2}{b(1+b^2)}\cdot(- \frac{b^2+1}{a-2})=\frac{2-a}{b}\\ [/tex]