Question

Scrieti sub forma unei singure puteri cu exponent numar natural:
a)25 la puterea 10 ori 5 la puterea 32 ori 125 la puterea 5
b) 9 la puterea 4 ori 27 la puterea 5 ori 3 la puterea 14
c) a la puterea 6 ori b la puterea 2 ori (a ori b) la puterea 4 ori b la putere 4
d)(a ori b) la puterea 12 impartit la a la puterea 4 ori b la puterea 3 ori (a la puterea 2 ori b)
e) 36 la puterea 5 ori 6 la puterea 5 ori 6 la puterea x+1

Answer 1

a)=(5²)^10×5^32×(5³)^5=
=5^20×5^32×5^15=
=5^(20+32+15)=5^67
b) =(3²)^4·(3³)^5·3^14=
=3^12·3^15·3^14=
=3^(12+15+14)=3^41
c) =a^6·b²·a^4·b^4·b^4=
=a^(6+4)·b(2+4+4)=a^10·b^10=(ab)^10
d)=a^12·b^12:a^4·b^3·a²·b=
=a^(12-4+2)·b(12-3+1)=a^10·b^10=(ab)^10
e)=(6²)^5·6^5·6^(x+1)=
=6^10·6^5·6^(x+1)=
=6^(10+5+x+1)=6^(16+x)
16+x=0
x=-16