Question

Se amesteca 200 g solutie de concentratie 20% cu 100 g solutie de concentratie 10%. Ce concentratie are solutia finala?

Answer 1

Răspuns:

Explicație:

ms1=200g

c1=20%

ms2=100g

c2=10%

cf=?

c1=md1 .100 :ms1

-se afla md1

md1=c1.ms1 :100

md1=20 . 200 :100=40g

-se afla md2 din a doua solutie

c2 = md2 .100 : ms2

md2=c2 . ms2 :100

md2=10 . 100 : 100=10g

-se afla md final

mdf=40g + 10g=50g

-se afla ms final

msf=200g +100g=300g

-se afla c final

cf= mdf .100 : msf

cf= 50. 100 : 300=16,6%

Answer 2

Răspuns: ms1=200g

                c1=20%

              ms2=100g

                 c2=10%

c1=md1*100/ms1

md1=20*200/100=40g

c2=md2*100/ms2

md2=c2*ms2/100

md2=10*100\100=10g

mdF=200g+100g=300g

cF=mdF*100/mjsF

cF=50*100/300=16.6%