Question

Se amesteca 200g solutie de concentratie 80% cu o solutie de 60% care contine 120g de sare si cu 100g de apa.Ce concentratie va avea solutia?

Answer 1

c3= md3x100/ms3                   unde   md3=md1+md2+ m,apa

sol.1 ms1=200g  c1=80%     ----> md1= 80x200/100= 160g
sol.2  md2= 120g    , c2=60%----> ms2=120X100/60= 200g

md3= 160g+120g=280g
ms3= 200g+200g+ 100g= 500g

c3= 280x100/500=........................calculeaza !!!!!

Answer 2

md1=c*ms/100=80*200g/100=160 g
ms2=md2*100/c=120g*100/60=200 g
mstotat=ms1+ms2+mapa=200+200+100=500 g
mdtotal =md1+md2=160 g+120 g=280 g
Cfinal=md total/ms total *100=280 g/500g*100=56%