Question

se considera functia f:/(-1)⇒R,f(x)=ײ-x-1supra x+1 a)calculati f"(x),x∈R/(-1)

Answer 1

[tex]( \frac{x^2-x-1}{x+1} )'= \frac{(2x-1)(x+1)-(x^2-x-1)}{(x+1)^2} = \frac{2x^2+x-1-x^2+x+1}{(x+1)^2} = (\frac{x^2+2x}{(x+1)^2}) ' \\ \\ = \frac{(2x+2)(x+1)^2-2(x^2+2x)}{(x+1)^4} = \frac{2(x+1)^3-2x(x+2)}{(x+1)^4}= \frac{2[(x+1)^3-x(x+2)}{(x+1)^4} [/tex]
mai inmultesti la numarator