Question

se considera functia g : R --> R, g(x) = 2x +1

$n = \sqrt{g(0) + g(1) + g(2) + ... + g(123)}$
dau coroana. repede plss​

Answer 1

Răspuns:

g(x)=2x+1

g(0)=1

g(1)=2+1=3

g(2)=2*2+1=5

g(1230=2*123+1=247

g(0)+g(1)=g(2)+...+g(123)=1+3+5+...+247

Aplicam  formula

1+3+5+...+(2n-1)=n²    unde 2n-1=2*123+1=247

2n=248

n=124

atunci

1+3+5+....+247=124²

n=√124²

n=124

Explicație pas cu pas: