Question

Se considera numerele A=7supra3√2 + 5√3supra2√6 - 5supra6√2                                              si B=6√12 (3supra√6 - √2supra√3) . Aflati  media geometrica media aritmetica si media armonica a celor 2 numere. Multumesc!! Scuze pentru ''supra''!!

Answer 1

7/3√2+5√3/2√6-5/6√2=(aducemi la acelasi numitor) (7*2√2+5*3√2-5√2)/12=2√2
6√12(3/√6-√2/√3)=6√12*(3√6-2√6)/6=√12*√6=2√18=6√2

mart=8√2/2=4√2
mg=√(2√2*6√2)=√24=2√6
marm=2/(1/2√2+1/6√2)=2/(4/6√2)=2/(2/3√2)=2*3√2/2=3√2