Question

Se considera numerele rationale pozitive a si b,pt care 6a/5b=0,48.Cat la suta reprezinta numarul a din nr b?
si aflati valoarea raportului 11a-2b/9a+6b
VA ROGGGG AJUTAATI-MA!!!!!!!!!!!!!!!!!!!!!

Answer 1

 [tex](1)\;\frac{6a}{5b}=\frac{48^{(4}}{100}=\frac{12}{25}\;\;;\;\; \frac{a}{b}=\frac{5\cdot12}{6\cdot25}=\frac{6\not0}{15\not0}=2/5=40^o/_o\\ (2)\;daca\;\frac{a}{b}=\frac{2}{5}\;atunci\;,\frac{a}{2}=\frac{b}{5}=... k\\ .\;\;\;\;\;a=2k\;si\;b=5k\;\;\Rightarrow\;\frac{11*2k-2*5k}{9*2k+6*5k}=\frac{12\not{k}}{48\not{k}}=\frac{1}{4}\;;[/tex]