Question

Se considera progresia geometrica ($b_{n}$) n≥1, ∀n∈N, in care $b_{1}$=3 si $b_{2}$=6. Sa se calculeze $b_{4}$.

Answer 1

b2=  b1*q  unde  q=ratia
6=3*q=>q=2
b4=b1*q³=3*8=24