Question

se considera proporția x-3y/x+3y=1/5 determinati raportul 4x+y/4x-y​

Answer 1

$\frac{x-3y}{x+3y}=\frac{1}{5} \implies 5(x-3y)=x+3y$

$\implies 5x-15y=x+3y$

$\implies 5x-x=3y+15y$

$\implies 4x=18y$
Inlocuim pe 4x in raportul care ne intereseaza:

$\frac{4x+y}{4x-y}=\frac{18y+y}{18y-y}=\frac{19y}{17y}=\frac{19}{17}$