Question

Se da: delta l=5 cm, m(masa)=5 kg k=?

Answer 1

delta l=5cm=0,05m
Fe=G
k•delta l=m•g
k•0,05=5•10
k=
$\frac{5 \times 10}{0.05} = \frac{ {50}^{100} }{ {0.05}^{100} } = \frac{5000}{5} = 1000$