Question

Se da urmatoarea formula: Na2CO3.
-raport de masa
-raport atomic
-masa moleculara
-compozitie procentuala

Answer 1

Na2CO3

raport atomic=r.a.=2Na:1C :3 O=2:1:3

raport de masa =r.m.=2ANa: AC :3AO=2.23: 12: 3.16=46:12:48=23:6:24

Masa moleculara= M= 46+12+48=106

Compozitie procentuala prin masa moleculara

106 g-------46g Na-------12 g C----------48 g O

100g-----------X------------Y--------------------Z

X=100.46:106=

Y=100.12:106=

Z=100.48:106=

Calculeaza!