Question

Se dau functiile f, g :R -IR , f(x) =2x-4 si g(x) =x la puterea 2 -3x
a)Calculati S1 =f(0) +f(1)+f(2) +f(3)
S2 =g(0) +g(1) +g(2) +g(3)
Dau coroana!

Answer 1

Răspuns:

s1= (2×0-4)+(2×1-4)+(2×3-4)= (-4)+(-2)+2

= -4

S2= 0 la a 2 -3×0 + 1 la a 2-3 + 2 la a 2-6+ 3 la a 2-9=1+(-2)+(-2)+0

1-2-2+0 =-5