Question

Se dau nr: n=3^40:(3^3×3^34)×(3^2+3×25):42 si m=411014-411×2^3×5^3-2^3×7^2:28.Calculate m×n m+n.

Answer 1

n= 3 la puterea 40 : 3 la puterea 37 x (9+3 x 25):42
n=3 la puterea  3 x (9+75):42
n= 27 x 84 : 42
n= 2268:42
n=54
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m=411014-411 x 8 x  125 - 8 x 49 :28
m= 411014 - 3288 x 125 - 392 : 28
m= 411014 - 411000 -14 = 0
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 M x N = 54  x  0 = 0
M+ N = 54+0= 54