Question

se dau numerele a= (2+√3)² + (2-√3)² si b = 56 a) Aratati ca a = 14 b) calculati media geometrica a numerelor a si b​

Answer 1

a) a = (2+√3)²+(2-√3)² =

= 4+4√3+√3² + 4-4√3+√3² =

= 8+3+3 = 14

b) m_g = √(a*b) = √(14*56) = √784 = √28² = 28