Question

Se monotorizeaza 1 kmol de C6H6 cu 400 kg nitrant ce contine 30% HNO3 si 60% H2SO4. Acidul rezidual va avea o concentratie de HNO3 egala cu ?

Answer 1

1kmol  63kg                        18kg
C₆H₆ + HNO₃ -> C₆H₅-NO₂ + H₂O
1kmol  a=63kg                    b=18kg
in urma reactiei, 63kg de HNO₃ nitreaza benzenul, diluand amestecul nitrant ramas cu 18kg apa
masa amestecului nitrant ramas = 400-63+18=355kg amestec nitrant final
mHNO₃initial=30% din 400kg=0,3*400=120kg HNO₃
mHNO₃ramasa=120-63=57kg HNO₃
%HNO₃=57*100%/355=16,05%