Question

Se oxideaza n- propanolul respectiv izopropanolul cu solutie de K2Cr2O7 /H2SO4 , rapoartele molare K2Cr2O7 : npropanol respectiv K2Cr2O7 : Izopropanol vor fi ?

Answer 1

3CH3-CH2-CH2-OH + K2Cr2O7 + 4H2SO4 ---> 3CH3-CH2-C=O-H + K2SO4 + Cr2(SO4)3 + 7H2O

C⁻¹ -2e⁻---> C⁺¹ se oxideaza (ag. red)    ||6||3

Cr2⁺⁶ +6e⁻---> Cr2⁺³ se reduce (ag.ox)  ||2||1

raport molar propanol:K2Cr2O7=3:1

3CH3-CH(OH)-CH3 + K2Cr2O7 + 4H2SO4 ---> 3CH3-C(=O)-CH3 + K2SO4 + Cr2(SO4)3 + 7H2O

C⁰ -2e⁻---> C⁺² se oxideaza (ag.red)    ||6||3

Cr2⁺⁶ +6e⁻ ---> Cr2⁺³ se reduce (ag.ox)  ||2||1

Raport molar izopropanol:K2Cr2O7(bicromat de potasiu)= 3:1

Rapoartele molare sunt similare/identice/la fel :D