Question

Se stie ca [tex] \frac{x}{7} = \frac{y}{6} = \frac{z}{5}
[/tex] si x+y+z = 32.
Calculati pe x, y si z .

Answer 1

x/7=y/6=z/5=k
x/7=k⇒x=7k
y/6=k⇒y=6k
z/5=k⇒z=5k
inlocuim in relatia x+y+x=32⇒
7k+6k+5k=32
18k=32
k=32/18 simplificam cu 2
k=16/9
x=7k=7·16/9=112/9⇒x=12,(4)
y=6k=6·16/9=96/9⇒y=10,(6)
z=5k=5·16/9=80/9⇒z=8,(8)

Answer 2

x+y+z = 32
$\frac{x+y+z}{7+6+5} = \frac{32}{18} = 1,(7)$ care se rotunjeste la 2
[tex] \frac{x}{7} = 2 [/tex] ⇒ $x=7*2$ ⇒ $x = 14$
[tex] \frac{y}{6} = 2 [/tex] ⇒ $x=6*2$ ⇒ $x = 12$
[tex] \frac{z}{5} = 2 [/tex] ⇒ $x=5*2$ ⇒ $x = 10$

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