Question

se supun ă ferii 416 g amestec metan,etan,propan iar alcanii sunt in rap 1:2:3.Calc vol de aer si comp pricentuala masica a amestecului

Answer 1

16x+30y+44z=416

x/y=1/2=>y=2x => y=4 moli

x/z=1/3 =>z=3x =>z=6 moli

16x+30*2x+44*3x=416=>208x=416=>x=2 moli

CH4 + 2O2 = CO2 + 2H2O + Q

1mol CH4..........2moli O2
2moli CH4.........x=4 moli O2

C2H6 + 7/2O2 = 2CO2 + 3H2O + Q

1mol C2H6.............3,5 moli O2
4 moli C2H6..........x=14 moli O2

C3H8 + 5O2 = 3CO2 + 4H2O + Q

1mol C3H8...............5moli O2
6 moli C3H8............x=30 moli O2

nt O2 = 4+14+30=48 moli O2

V=22,4*48=1075,2L O2

Vaer=5VO2=5*1075,2=5376L aer

m CH4=2*16=32g 

mC2H6=4*30=120g

mC3H8=44*6=264g

m total = 32+120+264=416g

%CH4=mCH4/m amestec *100 = 32/416*100 = Calculeaza

Calculeaza si la restul...