Question

Semisuma a patru numere pare consecutive este 290. Gaseste numerele.

Clasa a IV culegeri

Answer 1

a,a+2,a+4,a+6-nr.
(a+a+2+a+4+a+6)/2=290
(4a+12)/2=290
4a+12=290×2
4a+12=580
4a=580-12
4a=568
a=568/4
a=142=>a+2=142+2=144
a+4=142+4=146
a+6=142+6=148

Answer 2

semisuma=suma :2 ....=> 290=(290*2):2....=> suma numerelor este 580

a+b+c+d=290*2 ...=> a+b+c+d= 580

avand in vedere ca sunt numere pare consecutive....=>

b=a+2
c=a+4
d=a+6

a+a+2+a+4+a+6=580
4a+12=580
4a=580-12
4a=568
a=568:4
a=142

b=142+2.....b=144
c=142+4.....c=146
d=146+6.....d=148

semisuma=> 144+146=290
suma=> 142+144+146+148=580