Question

sfertul sumei a patru numere consecutive pare este 89.afla numerele.     multumesc!

Answer 1

(2a+2a+2+2a+4+2a+6)/4=89

8a+12=4*89

8a+12=356

8a=356-12

8a=344

a=43

2a=43*2=86
2a+2=88
2a+4=90
2a+6=92

Answer 2

(a + a+2 + a+4 +a+6) : 4 = 89
4a +12= 356
4a =344
a = 86
b= 88
c= 90
d= 92
Asta e corect !