Question

Simplificarea raportului algebric

$\frac{x^{2}-9}{ x^{2}+3x} = \\ \\ \\ \\ Si \\ acesta \\ \\ \\ \\ \frac{ x^{2} -16}{ x^{2} -8x+15}=$

Answer 1

 [tex]... \;=\; \frac{(x-3)(x\not+3)}{x(x\not+3}=\frac{x-3}{x}\;;\\ ... \;=\;\frac{(x-4)(x+4)}{x^2-3x-5x+15}=\frac{(x-4)(x+4)}{x(x-3)-5(x-3)}=\frac{(x-4)(x+4)}{(x-3)(x-5)}=iredictibil\,![/tex]